UpdateTime 2020-12-04
函数、极限、连续 求极限 \displaystyle \lim_{n\to\infty} \left(\frac{1}{2}\tan\frac{\pi}{2^2} + \frac{1}{2^2}\tan\frac{\pi}{2^3} + \cdots + \frac{1}{2^n}\tan\frac{\pi}{2^{n+1}}\right)\displaystyle \lim_{n\to\infty} \left(\frac{1}{2}\tan\frac{\pi}{2^2} + \frac{1}{2^2}\